The “jailbreak method” call be applied to any root. In other words it works for a cube root, fourth root, fifth root, or any root with some slight modifications.
Example 1 ( Each of these examples are worked out in the video)
Simplify ∛16
Step 1 Create a factor tree
Step 2 Now determine who gets to “jailbreak” because you are working with a cube you look for triplets of like prime numbers
In this example there is one triplet of 2’s so they escape and one 2 remains under the radical which equals 2√2
How to Simplfy a fourth root
How to Simplfy a Cube Root
Simplifying Radicals Calculator
Simplify ∜512
Step 1 Create a factor tree
Simplify ∜81
Step 1 Create a factor tree
Step 2 Now determine who “ jailbreaks” This time you are working with a fourth root so you look for 4 like prime numbers
Step 3 There is one group of 4 like prime numbers so they escape and you have none left over so you have an even forth root of 3.
Step 4 ∜81=3
Step 2 Two groups of four 2's escape and one two remains. Remember, the problem involves simplfying a fourth root so you are looking for groups of four prime numbers that are the same.